A block of mass 10 kg is lying over rough horizontal platform moving with constant acceleration a = 0.5 m/s 2 (fig. 1) the coefficient of friction between block & platform is µ s = µ k = 0.1 (g = 10 m/s 2 ) -
(i) If block is at rest relative to platform then the frictional force on the block is –
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Verified by ExpertsThe correct answer is:
CHECK THE SOLUTION.
(i) : 
= ma 
= 5 
N
(ii) : 
= –µmg 
= –10 
N
(iii) : kx 0 cos θ = 5
k x 0 sin θ = 10
x 0 = 
m
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